5(9c-5)-[2(4c-3)+2]=0

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Solution for 5(9c-5)-[2(4c-3)+2]=0 equation:


Simplifying
5(9c + -5) + -1[2(4c + -3) + 2] = 0

Reorder the terms:
5(-5 + 9c) + -1[2(4c + -3) + 2] = 0
(-5 * 5 + 9c * 5) + -1[2(4c + -3) + 2] = 0
(-25 + 45c) + -1[2(4c + -3) + 2] = 0

Reorder the terms:
-25 + 45c + -1[2(-3 + 4c) + 2] = 0
-25 + 45c + -1[(-3 * 2 + 4c * 2) + 2] = 0
-25 + 45c + -1[(-6 + 8c) + 2] = 0

Reorder the terms:
-25 + 45c + -1[-6 + 2 + 8c] = 0

Combine like terms: -6 + 2 = -4
-25 + 45c + -1[-4 + 8c] = 0
-25 + 45c + [-4 * -1 + 8c * -1] = 0
-25 + 45c + [4 + -8c] = 0

Reorder the terms:
-25 + 4 + 45c + -8c = 0

Combine like terms: -25 + 4 = -21
-21 + 45c + -8c = 0

Combine like terms: 45c + -8c = 37c
-21 + 37c = 0

Solving
-21 + 37c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '21' to each side of the equation.
-21 + 21 + 37c = 0 + 21

Combine like terms: -21 + 21 = 0
0 + 37c = 0 + 21
37c = 0 + 21

Combine like terms: 0 + 21 = 21
37c = 21

Divide each side by '37'.
c = 0.5675675676

Simplifying
c = 0.5675675676

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